Re: Escape wildcard problems.

From: "Thom Brown" <thombrown(at)gmail(dot)com>
To: "Craig Ringer" <craig(at)postnewspapers(dot)com(dot)au>
Cc: "Alan Hodgson" <ahodgson(at)simkin(dot)ca>, pgsql-general(at)postgresql(dot)org
Subject: Re: Escape wildcard problems.
Date: 2008-10-24 16:31:01
Message-ID: bddc86150810240931x6b9351d9x7aa815cf4599e53d@mail.gmail.com
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Or you could use:

SELECT name
FROM templates
WHERE name ~ '\_cont\_';

This does it as a regular expression.

~* '\_aa\_';

On Fri, Oct 24, 2008 at 5:07 PM, Craig Ringer
<craig(at)postnewspapers(dot)com(dot)au> wrote:
> Alan Hodgson wrote:
>> On Friday 24 October 2008, "Gauthier, Dave" <dave(dot)gauthier(at)intel(dot)com> wrote:
>>> I read in the docs (section 9.7.1) that the backslash... \ ... is the
>>> default escape char to use in "like" expressions. Yet when I try it, it
>>> doesn't seem to work the ay I expect. Here's an example...
>>>
>>> select name from templates where name like '%\_cont\_%';
>>>
>>
>> Use double \\ for underscores. I don't know why it's necessary, but it works
>> here.
>
> Here's why. See the documentation for more information:
>
>
> craig=> show standard_conforming_strings;
> standard_conforming_strings
> -----------------------------
> off
> (1 row)
>
> craig=> SELECT '%\_cont\_%';
> WARNING: nonstandard use of escape in a string literal
> LINE 1: SELECT '%\_cont\_%';
> ^
> HINT: Use the escape string syntax for escapes, e.g., E'\r\n'.
> ?column?
> ----------
> %_cont_%
> (1 row)
>
> craig=> SELECT E'%\\_cont\\_%';
> ?column?
> ------------
> %\_cont\_%
> (1 row)
>
> craig=> set standard_conforming_strings = 1;
> SET
>
> craig=> SELECT '%\_cont\_%';
> ?column?
> ------------
> %\_cont\_%
> (1 row)
>
>
>
> --
> Craig Ringer
>
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