Re: Have I found an interval arithmetic bug?

From: Isaac Morland <isaac(dot)morland(at)gmail(dot)com>
To: Zhihong Yu <zyu(at)yugabyte(dot)com>
Cc: Bruce Momjian <bruce(at)momjian(dot)us>, John W Higgins <wishdev(at)gmail(dot)com>, PostgreSQL-development <pgsql-hackers(at)postgresql(dot)org>
Subject: Re: Have I found an interval arithmetic bug?
Date: 2021-04-03 01:23:51
Message-ID: CAMsGm5errRXqOOt2r-uSDYqn301s_tQMQdJHLPmTXcc+EOLEfQ@mail.gmail.com
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On Fri, 2 Apr 2021 at 21:08, Zhihong Yu <zyu(at)yugabyte(dot)com> wrote:

> Hi,
> I got a local build with second patch where:
>
> yugabyte=# SELECT interval '0.3 years' + interval '0.4 years' -
> interval '0.7 years';
> ?column?
> ----------
> 1 mon
>
> I think the outcome is a bit unintuitive (I would expect result close to
> 0).
>

That's not fundamentally different from this:

odyssey=> select 12 * 3/10 + 12 * 4/10 - 12 * 7/10;
?column?
----------
-1
(1 row)

odyssey=>

And actually the result is pretty close to 0. I mean it’s less than 0.1
year.

I wonder if it might have been better if only integers had been accepted
for the components? If you want 0.3 years write 0.3 * '1 year'::interval.
But changing it now would be a pretty significant backwards compatibility
break.

There's really no avoiding counterintuitive behaviour though. Look at this:

odyssey=> select 0.3 * '1 year'::interval + 0.4 * '1 year'::interval - 0.7
* '1 year'::interval;
?column?
------------------
-1 mons +30 days
(1 row)

odyssey=> select 0.3 * '1 year'::interval + 0.4 * '1 year'::interval - 0.7
* '1 year'::interval = '0';
?column?
----------
t
(1 row)

odyssey=>

In other words, doing the “same” calculation but with multiplying 1 year
intervals by floats to get the values to add, you end up with an interval
that while not identical to 0 does compare equal to 0. So very close to 0;
in fact, as close to 0 as you can get without actually being identically 0.

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