From: | "David G(dot) Johnston" <david(dot)g(dot)johnston(at)gmail(dot)com> |
---|---|
To: | robertmccollistergreene(at)hotmail(dot)com, pgsql-bugs(at)lists(dot)postgresql(dot)org |
Subject: | Re: BUG #18061: The psql -v variable option does not work for the -c command option |
Date: | 2023-08-20 16:58:01 |
Message-ID: | CAKFQuwag6FeVC7fPO=cTGt_iOTy7rnum48cgHCn0p83xr+MLeA@mail.gmail.com |
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Lists: | pgsql-bugs |
On Sun, Aug 20, 2023 at 8:56 AM PG Bug reporting form <
noreply(at)postgresql(dot)org> wrote:
> The following bug has been logged on the website:
>
> Bug reference: 18061
> Logged by: Robert Greene
> Email address: robertmccollistergreene(at)hotmail(dot)com
> PostgreSQL version: 15.4
> Operating system: Windows, Linux
> Description:
>
> psql -v v1=1 -c "select col from table where colname=:v1;"
>
Yes, since psql variables are not parsable by the server the following
sentence in the documentation for -c explains your observation:
> command must be either a command string that is completely parsable by
the server (i.e., it contains no psql-specific features), or a single
backslash command.
David J.
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