From: | Steve Midgley <science(at)misuse(dot)org> |
---|---|
To: | "David G(dot) Johnston" <david(dot)g(dot)johnston(at)gmail(dot)com> |
Cc: | Baxter Allen <baxter(dot)allen(at)gmail(dot)com>, "pgsql-sql(at)postgresql(dot)org" <pgsql-sql(at)postgresql(dot)org> |
Subject: | Re: How to display multiple rows in 1 row |
Date: | 2017-01-11 04:01:52 |
Message-ID: | CAJexoSKdVebRKKNXN3TCsyLh9G+o7PyifCUw75o_P0ZrNxyEJA@mail.gmail.com |
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Lists: | pgsql-sql |
On Tue, Jan 10, 2017 at 7:40 PM, David G. Johnston <
david(dot)g(dot)johnston(at)gmail(dot)com> wrote:
> On Tuesday, January 10, 2017, Steve Midgley <science(at)misuse(dot)org> wrote:
>
>>
>> Given the DDL at the bottom of my email (what I used to test), this sql
>> statement works, I think:
>>
>> select * from
>> (select a.id as a_id, * from table_a a
>> left join table_b b on a.id=b.id) a1
>> join table_c c on a1.a_id = c.id
>>
>>
>> Returns
>>
>> "1.table_c";"1.table_c";1;"";;;"1.table_c";4;3
>> "2.table_c";"2.table_c";2;"";;;"2.table_c";3;4
>> "3.table_c";"3.table_c";3;"";;;"3.table_c";2;21
>>
>>
> Aside from executing without error I don't see how this works at all.
> You cannot solve the posed problem by rearranging simple joins.
>
> David J.
>
Ugh - my bad - I only checked the table_c data in my results and got what I
was expecting. I'm out of time tonight to play with this - apologies for
bogus response. I'll see if I can rectify tomorrow.
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