Re: how many times

something like this.
select
sum (case when buc = 1 then 1 else 0 end) _1_8_sec,
sum (case when buc = 2 then 1 else 0 end) _2_8_sec,
sum (case when buc = 3 then 1 else 0 end) _3_8_sec,
sum (case when buc = 4 then 1 else 0 end) _4_8_sec,
sum (case when buc = 5 then 1 else 0 end) _5_8_sec,
sum (case when buc = 6 then 1 else 0 end) _6_8_sec,
sum (case when buc = 7 then 1 else 0 end) _7_8_sec,
sum (case when buc = 8 then 1 else 0 end) _1_sec,
sum (case when buc = 9 then 1 else 0 end) _8_8_sec,
sum (case when buc = 10 then 1 else 0 end) _10_8_sec,
sum (case when buc = 11 then 1 else 0 end) _11_8_sec,
sum (case when buc = 12 then 1 else 0 end) _12_8_sec,
count(*) cnt
from
(select width_bucket( temp_time, 0, 1500 , 11) buc from
mikes_debug_log_vals2 where temp_time is not null) x

On Wed, Aug 23, 2017 at 11:03 AM, Campbell, Lance <lance(at)illinois(dot)edu>
wrote:

> I am not for sure how to do the below. I was hoping someone could share
> their thoughts.
>
>
>
> Assume I have a table called T1. It contains a single filed called
> “viewed” that is of type timestamp.
>
>
>
> Every time someone views a particular web page we insert the current
> timestamp into T1.
>
>
>
> Now I need to ask this business question:
>
>
>
> On average in any consecutive five minute time frame how many times is the
> web page viewed?
>
>
>
> Thanks,
>
>
>
> Lance
>