Re: Backward compatibility

From: Igor Korot <ikorot01(at)gmail(dot)com>
To: Tom Lane <tgl(at)sss(dot)pgh(dot)pa(dot)us>
Cc: John McKown <john(dot)archie(dot)mckown(at)gmail(dot)com>, "David G(dot) Johnston" <david(dot)g(dot)johnston(at)gmail(dot)com>, John R Pierce <pierce(at)hogranch(dot)com>, pgsql-general <pgsql-general(at)postgresql(dot)org>
Subject: Re: Backward compatibility
Date: 2017-07-22 16:22:32
Message-ID: CA+FnnTzM44AMqwZDv2p-qiBouTNmwFtn9J3dtFbDZf6-nYWEnw@mail.gmail.com
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Thx.
The split_part() works perfectly.

On Sat, Jul 22, 2017 at 10:49 AM, Tom Lane <tgl(at)sss(dot)pgh(dot)pa(dot)us> wrote:
> Igor Korot <ikorot01(at)gmail(dot)com> writes:
>> But it works incorrectly - it should return:
>> 9.5.7 on x86_64-redhat-linux-gnu, compiled by gcc (GCC) 6.3.1 20161221
>> (Red Hat 6.3.1-1), 64-bit
>> i.e. without the word "PosgreSQL", since '\s' should match the (first)
>> space in the version().
>
> position() is not a regex operation, it's just a plain substring match.
>
> regression=# SELECT position( '\s' in version() ) ;
> position
> ----------
> 0
> (1 row)
>
> You hardly need any flexibility for this anyway, so I'd just do
>
> regression=# SELECT position( ' ' in version() ) ;
> position
> ----------
> 11
> (1 row)
>
> Although possibly what you really want is split_part().
>
> regression=# select split_part(version(), ' ', 2);
> split_part
> ------------
> 9.5.7
> (1 row)
>
> regards, tom lane

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