Re: Query, view join question.

From: vhikida(at)inreach(dot)com
To: "Tom Lane" <tgl(at)sss(dot)pgh(dot)pa(dot)us>
Cc: "Joost Kraaijeveld" <j(dot)kraaijeveld(at)askesis(dot)nl>, vhikida(at)inreach(dot)com, "Pgsql-General" <pgsql-general(at)postgresql(dot)org>
Subject: Re: Query, view join question.
Date: 2005-01-06 19:47:52
Message-ID: 59009.146.74.1.99.1105040872.squirrel@146.74.1.99
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I think there is an echo in here :) It's probably me. I pass for the rest
of this thread.

> "Joost Kraaijeveld" <J(dot)Kraaijeveld(at)Askesis(dot)nl> writes:
>> CREATE OR REPLACE VIEW even AS
>> SELECT DISTINCT abo_his.klantnummer,
>>> abo_his.artikelnummer, abo_his.code_retour,
>>> abo_klt.aantal_abonnementen, abo_klt.afgewerkt
>> FROM abo_his
>> JOIN abo_klt ON abo_his.klantnummer = abo_klt.klantnummer
>> WHERE abo_his.abonnement = 238
>> ORDER BY abo_his.klantnummer, abo_his.artikelnummer,
>>> abo_his.code_retour, abo_klt.aantal_abonnementen, abo_klt.afgewerkt;
>
>> In the table abo_klt there is no record where abo_klt.abonnement = 238
>> and abo_klt.afgewerkt > 0:
>
>> munt=# select * from abo_klt where abonnement = 238 and afgewerkt > 0;
>
> Yes, but the join isn't testing abo_klt.abonnement. It's testing
> abo_his.abonnement. If there's a reason to think that rows in the two
> tables with the same klantnummer must also have the same abonnement,
> you have not said what it is.
>
> regards, tom lane
>
> ---------------------------(end of broadcast)---------------------------
> TIP 8: explain analyze is your friend
>

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