| From: | Tom Lane <tgl(at)sss(dot)pgh(dot)pa(dot)us> |
|---|---|
| To: | "Joost Kraaijeveld" <J(dot)Kraaijeveld(at)Askesis(dot)nl> |
| Cc: | vhikida(at)inreach(dot)com, "Pgsql-General (E-mail)" <pgsql-general(at)postgresql(dot)org> |
| Subject: | Re: Query, view join question. |
| Date: | 2005-01-06 19:34:36 |
| Message-ID: | 19054.1105040076@sss.pgh.pa.us |
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| Lists: | pgsql-general |
"Joost Kraaijeveld" <J(dot)Kraaijeveld(at)Askesis(dot)nl> writes:
> CREATE OR REPLACE VIEW even AS
> SELECT DISTINCT abo_his.klantnummer,
>> abo_his.artikelnummer, abo_his.code_retour,
>> abo_klt.aantal_abonnementen, abo_klt.afgewerkt
> FROM abo_his
> JOIN abo_klt ON abo_his.klantnummer = abo_klt.klantnummer
> WHERE abo_his.abonnement = 238
> ORDER BY abo_his.klantnummer, abo_his.artikelnummer,
>> abo_his.code_retour, abo_klt.aantal_abonnementen, abo_klt.afgewerkt;
> In the table abo_klt there is no record where abo_klt.abonnement = 238 and abo_klt.afgewerkt > 0:
> munt=# select * from abo_klt where abonnement = 238 and afgewerkt > 0;
Yes, but the join isn't testing abo_klt.abonnement. It's testing
abo_his.abonnement. If there's a reason to think that rows in the two
tables with the same klantnummer must also have the same abonnement,
you have not said what it is.
regards, tom lane
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