why copy tuple in the end of trigger when nothing changed in NEW, OLD record variable

From: 汪琦 <billywq(at)163(dot)com>
To: pgsql-hackers(at)postgresql(dot)org <pgsql-hackers(at)postgresql(dot)org>
Subject: why copy tuple in the end of trigger when nothing changed in NEW, OLD record variable
Date: 2008-06-10 09:50:03
Message-ID: 484E4E80.048232.25430@m5-81.163.com
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hello, everyone:

version 8.3.0 in function plpgsql_exec_trigger.

in a trigger, if NEW is returned as the result and we do nothing to NEW.

for example, we have a table like this:

create table test (a int);
insert into test values(1);

and a trigger like:

create or replace function test_trigger() returns trigger as $$
begin
return new;
end; $$language plpgsql;

create trigger before_update_test before update
on test for each row execute procedure test_trigger();

in this trigger, we don't change the value of NEW.

than execute:

update test set a = 3;

after execution:

/* Copy tuple to upper executor memory */
rettup = SPI_copytuple((HeapTuple) (estate.retval));

we come to function ExecUpdate():

HeapTuple newtuple;
newtuple = ExecBRUpdateTriggers(estate, resultRelInfo,
tupleid, tuple);

Since the trigger's return value is copied to another memory address, the newtuple is impossible equal to the oldtuple.

so the following condition:

if (newtuple != tuple) /* modified by Trigger(s) */
{

is FALSE for ever.

I think we can add some judgment conditions in function plpgsql_exec_trigger() to avoid this problem.

        billywq(at)163(dot)com
          2008-06-10

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