From: | Manfred Koizar <mkoi-pg(at)aon(dot)at> |
---|---|
To: | Nicholas Allen <nallen(at)freenet(dot)co(dot)uk> |
Cc: | Tom Lane <tgl(at)sss(dot)pgh(dot)pa(dot)us>, Peter Childs <blue(dot)dragon(at)blueyonder(dot)co(dot)uk>, pgsql-sql(at)postgresql(dot)org |
Subject: | Re: Debugging postmaster to fix possible bug in Postgres? Followup to "How do you select |
Date: | 2003-02-13 19:39:38 |
Message-ID: | 44sn4vgisulljq45qo35bug12sed1ll3ce@4ax.com |
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Lists: | pgsql-sql |
On Thu, 13 Feb 2003 18:28:50 +0100, Nicholas Allen
<nallen(at)freenet(dot)co(dot)uk> wrote:
>Because the WHERE clause is directly affected by the ORDER BY clause.
No, it's not (at least in your query).
> If you
>leave out the order by clause then the row count will be completely different
>and therefore wrong.
I must be missing something. Please give an example.
> The ORDER BY clause is just as important as the WHERE
>clause when counting rows. It should be possible to get a count for the rows
>for any query that can be done which can return row data as I understand it.
If you have a set of numbers, say {1, 9, 5, 3, 7}, and want to know
how many elements of the set are <= 7 (SELECT COUNT(*) FROM s WHERE
n<=7), you simply look a each element - no matter in what order - and
increase your counter, if the element satifies your condition. I
can't see how you get different numbers when you count {1, 3, 5, 7},
{1, 5, 3, 7} or any other permutation.
>I have tried to find a definition for SQL SELECT command but everywhere I have
>looked so far makes no mention of this being invalid SQL syntax. Can you let
>me know where you got this information?
SQL92 says:
<direct select statement: multiple rows> ::=
<query expression> [ <order by clause> ]
[...]
3) Let T be the table specified by the <query expression>.
4) If ORDER BY is specified, then each <sort specification> in the
<order by clause> shall identify a column of T.
Servus
Manfred
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