From: | Andrew Hammond <ahammond(at)ca(dot)afilias(dot)info> |
---|---|
To: | Leon Stringer <leon(dot)stringer(at)ntlworld(dot)com> |
Cc: | pgsql-sql(at)postgresql(dot)org |
Subject: | Re: Consecutive row count query |
Date: | 2005-03-17 23:35:39 |
Message-ID: | 423A144B.2010304@ca.afilias.info |
Views: | Raw Message | Whole Thread | Download mbox | Resend email |
Thread: | |
Lists: | pgsql-sql |
You could hack it using a custom aggregate. NB: you'll want to reset the
categorizer_seq every now and then. And this isn't safe for concurrent
queries. You could make it safe for concurrent queries by using a
complex type for STYPE, but I didn't bother. I also haven't debugged
this, but I think it expresses the concept.
CREATE SEQUENCE categorizer_seq;
CREATE OR REPLACE FUNCTION categorizer_func (string, string) RETURNS
bigint VOLATILE CALLED ON NULL INPUT AS '
SELECT CASE WHEN $1 = $2
THEN (SELECT last_value FROM categorizer_seq)
ELSE nextval(''categorizer_seq'')
END AS category
' LANGUAGE SQL;
CREATE AGGREGATE categorizer (
BASETYPE = text,
SFUNC = categorizer_func,
STYPE = text,
INITCOND = ''
);
SELECT col1, count(*)
FROM (
SELECT col1, cagetorizer(col1) AS category
FROM mytable
ORDER BY col_order
) tmp
GROUP BY (col1, category);
Leon Stringer wrote:
> Hi,
>
> I wondered if anyone could answer the following question:
>
> If I have a table such as the one below:
>
> col1 col_order
> -----------
> Apple 1
> Apple 2
> Orange 3
> Banana 4
> Apple 5
>
> Is there a way I can get the following results:
>
> Apple 2
> Orange 1
> Banana 1
> Apple 1
>
> i.e. Each row is printed ordered by col_order but consecutive
> appearances of the same col1 result in only a single line in the result
> with the number of consecutive appearances.
>
> Obviously I could store the table as:
>
> col1 col_order col_count
> --------------------------
> Apple 1 2
> Orange 2 1
> Banana 3 1
> Apple 4 1
>
> But since (in my intended table) most rows will have col_count = 1, this
> seems like unnecessary normalization (and semantically "wrong").
>
> Thanks in advance for any help,
>
> Leon Stringer
>
>
>
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