From: | Stephan Szabo <sszabo(at)megazone(dot)bigpanda(dot)com> |
---|---|
To: | Josh Berkus <josh(at)agliodbs(dot)com> |
Cc: | Jan Wieck <JanWieck(at)Yahoo(dot)com>, Markus Bertheau <twanger(at)bluetwanger(dot)de>, olly(at)lfix(dot)co(dot)uk, pgsql-sql(at)postgresql(dot)org |
Subject: | Re: multi column foreign key for implicitly unique columns |
Date: | 2004-08-18 17:45:35 |
Message-ID: | 20040818104151.Y6662@megazone.bigpanda.com |
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Thread: | |
Lists: | pgsql-sql |
On Wed, 18 Aug 2004, Josh Berkus wrote:
> > In the case that a table constraint is a referential constraint,
> > the table is referred to as the referencing table. The referenced
> > columns of a referential constraint shall be the unique columns of
> > some unique constraint of the referenced table.
>
> Missed that one. Interesting. AFAIK, the uniqueness of referenced columns is
> NOT a requirement of Relaitonal Algebra. So why does SQL require it?
>
> Maybe I'll ask Joe Celko after he finishes moving to Austin.
>
> I have my own issue that forced me to use triggers. Given:
>
> table users (
> name
> login PK
> status
> etc. )
>
> table status (
> status
> relation
> label
> definition
> PK status, relation )
>
> the relationship is:
> users.status = status.status AND status.relation = 'users';
>
> This is a mathematically definable constraint, but there is no way in standard
> SQL to create an FK for it. This is one of the places I point to whenever
> we have the "SQL is imperfectly relational" discussion.
Well, I think SQL does give a way of specifying that constraint through
assertions and check constraints with subselects. We just don't support
either of those constructs.
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