From: | Mike Nolan <nolan(at)gw(dot)tssi(dot)com> |
---|---|
To: | pgsql-general(at)postgresql(dot)org (pgsql general list) |
Subject: | Select/Group by/Order by question |
Date: | 2004-04-08 23:49:23 |
Message-ID: | 200404082349.i38NnN45017008@gw.tssi.com |
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Lists: | pgsql-general |
I'm trying to create a summary log by hour. Here's the query (somewhat
simplified):
select to_char(mtrantime,'mm-dd hh AM') as datetime,
count(*) as tot from memtran
group by datetime
order by datetime;
The problem is this produces the data in the following order:
datetime | tot
-------------+-----
04-08 01 PM | 14
04-08 02 PM | 15
04-08 03 PM | 23
04-08 07 AM | 8
04-08 08 AM | 54
04-08 09 AM | 30
04-08 10 AM | 11
04-08 11 AM | 10
04-08 11 PM | 7
04-08 12 PM | 10
What I'd really like is to get it in chronological order by hour:
04-08 07 AM | 8
04-08 08 AM | 54
04-08 09 AM | 30
04-08 10 AM | 11
04-08 11 AM | 10
04-08 12 PM | 10
04-08 01 PM | 14
04-08 02 PM | 15
04-08 03 PM | 23
04-08 11 PM | 7
I would prefer not to show the time of day in 24 hour format, but
there doesn't appear to be a way to order by something that
isn't in the select and group by clause and I don't want to display
the hour twice.
Putting the AM/PM before the HH (which looks a bit clumsy) almost works,
except that 12PM gets sorted to the bottom after 11PM.
Is there an easy way around this?
--
Mike Nolan
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