From: | Roberto Mello <rmello(at)cc(dot)usu(dot)edu> |
---|---|
To: | Graham Vickrage <graham(at)digitalplanit(dot)com> |
Cc: | pgsql-sql(at)postgresql(dot)org |
Subject: | Re: Group by date_part |
Date: | 2001-07-10 19:36:23 |
Message-ID: | 20010710133623.A27302@cc.usu.edu |
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Lists: | pgsql-sql |
On Tue, Jul 10, 2001 at 08:04:55PM +0100, Graham Vickrage wrote:
>
> The statement I have only selects the count if there is at least 1 order for
> a particular day, which make sense.
>
> I however need a count of 0 for days that don't have any. Can anyone help?
>
> SQL:
>
> SELECT date_part('day', date), count(*)
> FROM client_order WHERE (date >= '01/05/01' AND date < '01/06/01') AND
> status = 'Processing'
> GROUP BY date_part('day', date);
Didn't look very hard, but can't you just add a:
CASE WHEN count(*) > 0 THEN count(*) ELSE 0 END AS count
-Roberto
--
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Roberto Mello - Computer Science, USU - http://www.brasileiro.net
http://www.sdl.usu.edu - Space Dynamics Lab, Developer
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