From: | PG Bug reporting form <noreply(at)postgresql(dot)org> |
---|---|
To: | pgsql-bugs(at)lists(dot)postgresql(dot)org |
Cc: | ochedru(at)gmail(dot)com |
Subject: | BUG #17930: Regression in DISABLE TRIGGER ALL |
Date: | 2023-05-12 07:52:13 |
Message-ID: | 17930-73168e744fdf85c0@postgresql.org |
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Lists: | pgsql-bugs |
The following bug has been logged on the website:
Bug reference: 17930
Logged by: Olivier Chédru
Email address: ochedru(at)gmail(dot)com
PostgreSQL version: 15.3
Operating system: Linux
Description:
Hi!
The following script creates a partition table with a foreign key and works
fine on PostgreSQL 14:
begin;
create table a(id int primary key);
create table b(id int primary key, a_id int not null references a(id))
partition by range(id);
create table b_default(like b including defaults including constraints);
alter table b attach partition b_default default;
alter table b disable trigger all;
commit;
On PostgresSQL 15, it fails on DISABLE TRIGGER ALL:
ERROR: trigger "RI_ConstraintTrigger_c_20196703" for table "b_default" does
not exist
It seems to use a wrong trigger name. In this case,
RI_ConstraintTrigger_c_20196703 is the name of a trigger defined on the
parent table b.
Thank you.
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