From: | Tom Lane <tgl(at)sss(dot)pgh(dot)pa(dot)us> |
---|---|
To: | ochedru(at)gmail(dot)com |
Cc: | pgsql-bugs(at)lists(dot)postgresql(dot)org |
Subject: | Re: BUG #17930: Regression in DISABLE TRIGGER ALL |
Date: | 2023-05-12 13:39:00 |
Message-ID: | 1315366.1683898740@sss.pgh.pa.us |
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Lists: | pgsql-bugs |
PG Bug reporting form <noreply(at)postgresql(dot)org> writes:
> The following script creates a partition table with a foreign key and works
> fine on PostgreSQL 14:
> begin;
> create table a(id int primary key);
> create table b(id int primary key, a_id int not null references a(id))
> partition by range(id);
> create table b_default(like b including defaults including constraints);
> alter table b attach partition b_default default;
> alter table b disable trigger all;
> commit;
> On PostgresSQL 15, it fails on DISABLE TRIGGER ALL:
> ERROR: trigger "RI_ConstraintTrigger_c_20196703" for table "b_default" does
> not exist
It works for me with 15.3. I don't think you are actually running
15.3 (i.e., yesterday's minor release), because this symptom matches
a bug we fixed in 15.3.
regards, tom lane
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