retrieving all rows from a "tree" in one select - how ?

From: h012(at)ied(dot)com
To: pgsql-sql(at)postgresql(dot)org
Subject: retrieving all rows from a "tree" in one select - how ?
Date: 2002-08-09 21:36:35
Message-ID: no.Yo.N.nN.0208091650190.2280-100000@business.com
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Hi,

I realize that a relational database may not be ideal for storing (and
retrieving) tree-like strucutres, but it looks like you guys are doing
with PostgreSQL the impossible anyway.

Having table t of all nodes:

CREATE SEQUENCE nodeIDseq START 1;
CREATE TABLE t(
id int PRIMARY KEY DEFAULT NEXTVAL('nodeIDseq'),
parent int REFERENCES t,
mydata int4
);
INSERT INTO t VALUES (0,0);

I was wondering whether there is a known (and perhaps working) way to do
things like:

-- select a tree starting with node 1234 and all its descendants:
SELECT * FROM t WHERE id=1234 OR ANCESTOR(t.parent) IS 1234;

and
-- select the path from tree node 2345 to the root
SELECT * FROM t WHERE id=2345 OR DESCENTANT(t.parent) IS 2345;

(I've seen some terse soutions at
http://www.brasileiro.net/postgres/cookbook/view-recipes.adp?section_id=2&format=long
but they don't seem to be complete.)

(Also I've looket at ltrees from GiST, but "ltree" seems to require that
the ID attribute contains all ancestors.)

Thanks,

John

--
-- Gospel of Jesus is the saving power of God for all who believe --
## To some, nothing is impossible. ##
http://Honza.Vicherek.com/

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