From: | Pavel Stehule <pavel(dot)stehule(at)gmail(dot)com> |
---|---|
To: | Thomas Kellerer <spam_eater(at)gmx(dot)net> |
Cc: | pgsql-sql(at)postgresql(dot)org |
Subject: | Re: Problem with function returning a result set |
Date: | 2010-04-08 09:01:20 |
Message-ID: | j2o162867791004080201i773a63cfg6b3f9d233cf40417@mail.gmail.com |
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Thread: | |
Lists: | pgsql-sql |
2010/4/8 Thomas Kellerer <spam_eater(at)gmx(dot)net>:
> Hi,
>
> I'm playing around with functions returning result sets, and I have a
> problem with the following function:
>
> -- Create sample data
> CREATE TABLE employee (id integer, first_name varchar(50), last_name
> varchar(50));
> INSERT INTO employee values (1, 'Arthur', 'Dent');
> INSERT INTO employee values (2, 'Zaphod', 'Beeblebrox');
> INSERT INTO employee values (3, 'Ford', 'Prefect');
> COMMIT;
>
> -- Create the function
> CREATE OR REPLACE FUNCTION get_employees(name_pattern varchar)
> RETURNS TABLE(id integer, full_name text)
> AS
> $$
> BEGIN
>
> RETURN QUERY
> SELECT id, first_name||' '||last_name
> FROM employee
> WHERE last_name LIKE name_pattern ||'%';
> END
> $$
> LANGUAGE plpgsql;
>
> COMMIT;
>
> Now when I run:
>
> SELECT *
> FROM get_employees('D');
>
> I get one row returned which is correct, but the ID column is null (but
> should be 1). It does not depend which row(s) I select through the
> procedure. I also tried to change the datatype of the returned id to int8
> and an explicit cast in the SELECT statement, but to no avail.
>
> When I define the function using SQL as a language (with the approriate
> changes), the ID column is returned correctly.
>
> I'm using Postgres 8.4.3 on Windows XP
> postgres=> select version();
> version
> -------------------------------------------------------------
> PostgreSQL 8.4.3, compiled by Visual C++ build 1400, 32-bit
> (1 row)
>
> What am I missing?
there are collision between SQL and PLpgSQL identifiers.
RETURNS TABLE(id integer, full_name text) AS
$$
BEGIN
RETURN QUERY
SELECT e.id, e.first_name||' '||e.last_name
FROM employee e
WHERE e.last_name LIKE e.name_pattern ||'%';
END
$$
LANGUAGE plpgsql;
use aliases.
Regards
Pavel Stehule
>
> Regards
> Thomas
>
>
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