| From: | Peter Eisentraut <peter(dot)eisentraut(at)2ndquadrant(dot)com> |
|---|---|
| To: | "David G(dot) Johnston" <david(dot)g(dot)johnston(at)gmail(dot)com>, "David E(dot) Wheeler" <david(at)justatheory(dot)com> |
| Cc: | PostgreSQL-development <pgsql-hackers(at)postgresql(dot)org> |
| Subject: | Re: Does Type Have = Operator? |
| Date: | 2016-05-11 04:11:40 |
| Message-ID: | e237af07-7efa-c0d7-8d82-2d05e2812e47@2ndquadrant.com |
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| Lists: | pgsql-hackers |
On 5/10/16 9:16 PM, David G. Johnston wrote:
> Brute force: you'd have to query pg_amop and note the absence of a row
> with a btree (maybe hash too...) family strategy 3 (1 for hash)
> [equality] where the left and right types are the same and match the
> type in question.
While these are good thoughts, the implementation of DISTINCT actually
looks for an operator that is literally named "=".
--
Peter Eisentraut http://www.2ndQuadrant.com/
PostgreSQL Development, 24x7 Support, Remote DBA, Training & Services
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