Re: Partitioning by letter question

On Fri, Jan 29, 2010 at 3:24 PM, John Lister
<john(dot)lister-ps(at)kickstone(dot)com> wrote:
> Hi, I was wondering if this was possible. I'm trying to partition a table,
> which is straightforward enough thanks to the great documentation, but i
> have a question:
>
> If I partition using something like a product_id for example and have check
> constraints such as (id>=1000 and id<2000) then everything is fine and the
> planner correctly uses the right subset of the tables. However I would like
> to partition by the first letter and using something like this
> substr(word,1,1)='a' is ignored by the planner. From reading the docs I
> understand that complicated check constraints are ignored, but this doesn't
> seem overly complicated.
>
> Am i doing  something wrong or is there another better way to do this

Have you tried:

(word >= 'a' and word <'b')

?