| From: | "Pawel Socha" <pawel(dot)socha(at)gmail(dot)com> |
|---|---|
| To: | ss_postgres <ss(dot)postgres(at)gmail(dot)com> |
| Cc: | pgsql-admin(at)postgresql(dot)org |
| Subject: | Re: How to find the position of a characted in a string |
| Date: | 2008-12-08 07:14:22 |
| Message-ID: | cc4f12900812072314r161e191vc9d2d0364f187c89@mail.gmail.com |
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| Thread: | |
| Lists: | pgsql-admin |
2008/12/8 ss_postgres <ss(dot)postgres(at)gmail(dot)com>:
> Hi,
>
> I am trying to find the position of a character in a string which appears
> multiple times.
>
> The POSITION function returns the position of the character when it first
> occurs.
>
> For eg:
>
> select position ( ' ' in 'Hi How are you');
>
> This returns the result as "3".
>
>
> But i need to result to be
> 3
> 7
> 11
>
>
> Can anyone please let me know what would be the best way to do this.
>
> Thanks
>
My first things:
merlin=> select distinct(x.case) from (select (case when substring('Hi
How are you' from r for 1) = ' ' then r else null end) from
generate_series(0, length('Hi How are you')) as r) as x;
case
------
3
7
11
--
Pawel Socha
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