Re: distinct aggregate with complex type dont see the equality operator [solved]

using DISTINCT with complex types depends on an OPERATOR CLASS for
B-Tree-Indexes i found out. the error msg 'could not identify an
equality operator for type' was confusing.

i post this complete example. maybe someone else is running in this problem too.

regards,
thomas!

CREATE TYPE named_value AS (
value_name text,
value numeric
);

CREATE OR REPLACE FUNCTION named_value_lt(named_value, named_value)
RETURNS boolean AS $f$
SELECT $1.value_name < $2.value_name;
$f$ LANGUAGE sql IMMUTABLE STRICT;

CREATE OR REPLACE FUNCTION named_value_lt_eq(named_value, named_value)
RETURNS boolean AS $f$
SELECT $1.value_name <= $2.value_name;
$f$ LANGUAGE sql IMMUTABLE STRICT;

CREATE OR REPLACE FUNCTION named_value_eq(named_value, named_value)
RETURNS boolean AS $f$
SELECT $1.value_name = $2.value_name;
$f$ LANGUAGE sql IMMUTABLE STRICT;

CREATE OR REPLACE FUNCTION named_value_gt_eq(named_value, named_value)
RETURNS boolean AS $f$
SELECT $1.value_name >= $2.value_name;
$f$ LANGUAGE sql IMMUTABLE STRICT;

CREATE OR REPLACE FUNCTION named_value_gt(named_value, named_value)
RETURNS boolean AS $f$
SELECT $1.value_name > $2.value_name;
$f$ LANGUAGE sql IMMUTABLE STRICT;

CREATE OR REPLACE FUNCTION named_value_cmp(named_value, named_value)
RETURNS integer AS $f$
SELECT CASE
WHEN $1.value_name < $2.value_name THEN -1
WHEN $1.value_name = $2.value_name THEN 0
ELSE 1
END;
$f$ LANGUAGE sql IMMUTABLE STRICT;

CREATE OPERATOR < (
PROCEDURE = named_value_lt,
LEFTARG = named_value,
RIGHTARG = named_value,
COMMUTATOR = >
);

CREATE OPERATOR <= (
PROCEDURE = named_value_lt_eq,
LEFTARG = named_value,
RIGHTARG = named_value,
COMMUTATOR = >=
);

CREATE OPERATOR = (
PROCEDURE = named_value_eq,
LEFTARG = named_value,
RIGHTARG = named_value,
COMMUTATOR = =
);

CREATE OPERATOR >= (
PROCEDURE = named_value_gt_eq,
LEFTARG = named_value,
RIGHTARG = named_value,
COMMUTATOR = <=
);

CREATE OPERATOR > (
PROCEDURE = named_value_gt,
LEFTARG = named_value,
RIGHTARG = named_value,
COMMUTATOR = <
);

CREATE OPERATOR CLASS named_value_ops
DEFAULT FOR TYPE named_value USING btree AS
OPERATOR 1 < ,
OPERATOR 2 <= ,
OPERATOR 3 = ,
OPERATOR 4 >= ,
OPERATOR 5 > ,
FUNCTION 1 named_value_cmp(named_value, named_value);

CREATE OR REPLACE FUNCTION sum_final(named_value)
RETURNS numeric AS $f$
SELECT $1.value;
$f$ LANGUAGE sql IMMUTABLE STRICT;

CREATE OR REPLACE FUNCTION sum_accum(named_value, named_value)
RETURNS named_value AS $f$
SELECT ROW('', $1.value + $2.value)::named_value;
$f$ LANGUAGE sql IMMUTABLE STRICT;

CREATE AGGREGATE sum(
BASETYPE = named_value,
SFUNC = sum_accum,
STYPE = named_value,
FINALFUNC = sum_final,
INITCOND = "('',0)"
);
-- result is FALSE
SELECT ROW('foo', 5)::named_value = ROW('bar', 5)::named_value;

-- result is TRUE
SELECT ROW('foo', 5)::named_value = ROW('foo', 5)::named_value;

-- result is TRUE
SELECT ROW('foo', 4)::named_value = ROW('foo', 5)::named_value;

-- works for me
SELECT sum(ROW(name, wert)::named_value) FROM table1;

-- now works for me too
SELECT DISTINCT ROW(wert, name)::named_value FROM table1;
SELECT sum(DISTINCT ROW(name, wert)::named_value) FROM table1;