Re: use fopen unknown resource

On 8/27/21 3:50 PM, ourdiaspora wrote:
>
> ‐‐‐‐‐‐‐ Original Message ‐‐‐‐‐‐‐
>
> On Friday, August 27th, 2021 at 11:10 PM, Adrian Klaver <adrian(dot)klaver(at)aklaver(dot)com> wrote:
>
>> https://www.php.net/manual/en/pdo.pgsqlcopyfromfile.php
>>
>
> "
> public PDO::pgsqlCopyFromFile(
> string $table_name,
> string $filename,
> "
>
> Sorry but do not understand; the line does not explain what to write in the php file.

I'm not a PHP programmer, but I'm going to say it is filename as
described here:

https://www.php.net/manual/en/function.fopen.php

" filename

If filename is of the form ...
"

> The plan is to write an html file for a user to select a csv file to import into a database. The manual suggests that the file name is already known (e.g. https://www.php.net/manual/en/function.fgetcsv.php)

You are asking the user to select a file, so there should be some sort
of file reference at that point, correct?

Same for below.

>
> Instead of:
> "
> ...
> fopen("test.csv", "r"))
> ...
> "
>
> it would _not_ be possible to write, correct?:
> "
> ...
> fopen("", "r"))
>
>

--
Adrian Klaver
adrian(dot)klaver(at)aklaver(dot)com