| From: | James Bond <coolofall(at)hotmail(dot)com> | 
|---|---|
| To: | <pgsql-sql(at)postgresql(dot)org> | 
| Subject: | postgres sql help | 
| Date: | 2011-10-14 15:41:46 | 
| Message-ID: | SNT102-W49402A41C6B6599F082D35A8E10@phx.gbl | 
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| Thread: | |
| Lists: | pgsql-sql | 
hi, i am fairly new in postgresql, so if anyone can help me would be great
 
if i simply do:
 
select ver_no
from version
order by ver_no
 
the result will be something like this:
 
.1.3.1
.1.3.2.5.
.1.4.1.7.12
.1.4.11.14.7.
.1.4.3.109.1.
.1.4.8.66.
 
so as you can see first 3 lines are ok, but how to make 1.4.3.109 come 
before 1.4.11 because the third level "3" is smaller than "11".  i 
understand they are stored as char so i used split_part function to 
separate each numbers between "." in a separate column. but when i try 
to convert those column into integer, i am getting an error msg saying: 
ERROR:  invalid input syntax for type numeric: " "
 
here is my code:
 
select ver_no, duedate, status,
to_number(split_part(ver_no, '.', 2), '9999') a,
to_number(split_part(ver_no, '.', 3), '9999') b,
to_number(split_part(ver_no, '.', 4), '9999') c,
to_number(split_part(ver_no, '.', 5), '9999') d
 
 
from version
 
order by a,b,c,d
 
I am not sure if i am heading towards wrong direction but can someone please suggest or give me some other ideas to sort this.  
 
PS: i found some good solution in SQL Server but those commands are not used in postgreSQL.
Thanks in advance
- James
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