Re: What day is it - when it isn't NOW()?

From: tomg(at)sqlclinic(dot)net
To: Josh Berkus <josh(at)agliodbs(dot)com>
Cc: Postgres SQL List <pgsql-sql(at)postgreSQL(dot)org>
Subject: Re: What day is it - when it isn't NOW()?
Date: 2003-08-01 18:53:10
Message-ID: Pine.LNX.4.44.0308011445250.29369-100000@q8.nrnet.org
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On Fri, 1 Aug 2003, Josh Berkus wrote:

> Thomas,
>
> > than now()? I'm looking for something along the lines of:
> > SELECT to_char('2003-08-04', 'Day') without much success.
> >
>
> Well, you could try the online docs under "Functions and operators" <grin>.

Hey Josh, how goes...yeah I bumbled around date/time functions for awhile but
couldn't find the right syntax...maybe I need new glasses? ;-)

> Alternately, SELECT EXTRACT(dow FROM '2003-08-04') will give you a numerical
> (0-6) day of the week.

I tried this but I don't need an integer returned so I went with the
to_char() approach. Thanks for tip - and thanks to Rod as well.

On 1 Aug 2003, Rod Taylor wrote:

>
> SELECT to_char('2003-08-04'::date, 'Day');
>

This is what I went for as it is the closest to the MySQL/Oracle syntax
I use for the same purpose, particularly Oracle:

$query = qq |SELECT DATE_FORMAT('$start_date', '%W')| if ($dbtype eq 'mysql');
$query = qq |SELECT TO_CHAR('start_date'::date, 'Day') if ($dbtype eq 'postgres');
$query = qq |SELECT TO_CHAR(TO_DATE('$start_date'), 'Day') FROM DUAL| if ($dbtype eq 'oracle');

Thanks again fellas - have a nice weekend!

Cheers

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