Re: select distinct w/order by

From: "scott(dot)marlowe" <scott(dot)marlowe(at)ihs(dot)com>
To: Tom Lane <tgl(at)sss(dot)pgh(dot)pa(dot)us>
Cc: John Liu <johnl(at)emrx(dot)com>, <pgsql-general(at)postgresql(dot)org>
Subject: Re: select distinct w/order by
Date: 2004-03-31 22:35:26
Message-ID: Pine.LNX.4.33.0403311534410.26942-100000@css120.ihs.com
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On Wed, 31 Mar 2004, Tom Lane wrote:

> "John Liu" <johnl(at)emrx(dot)com> writes:
> > The original simple SQL -
> > select distinct atcode from TMP order by torder;
>
> This is not "simple", it is "broken SQL with an undefined result".
>
> If DISTINCT merges multiple rows with the same atcode, how are we
> supposed to know which row's value of torder to sort the merged
> row on?
>
> Your other database was no doubt making a random choice and giving
> you a random result ordering in consequence. You need to think harder
> about what behavior you really want.
>
> Once you can define the behavior (ie, just which torder you want to use)
> you can probably implement it with something like
>
> select atcode from
> (select distinct on (atcode) atcode, torder from table
> order by atcode, ???
> ) ss
> order by torder;
>
> where the ??? ordering determines which torder you get in each atcode group.
> See the SELECT DISTINCT ON example in the SELECT reference page.

I did it like this:

select atcode from table group by atcode order by max(toorder);

Is that equivalent?

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