Re: Still don't know how to build this string ?

The following function will convert a given list into a comma delimited
string (the argument should be the typ):

CREATE FUNCTION dima_list(int4) RETURNS text AS '
DECLARE
rec record;
list text;
BEGIN
list := '''';
FOR rec IN SELECT diam FROM zylinder WHERE typ = $1
list := list || rec.diam || ''; ''
END LOOP;
RETURN list;
END;
' LANGUAGE 'plpgsql';

Note that PL/PGSQL must be installed first, which can be done by typing

createlang plpgsql

at a shell prompt as a postgres super user.

Michael Fork - CCNA - MCP - A+
Network Support - Toledo Internet Access - Toledo Ohio

On Mon, 26 Mar 2001 juerg(dot)rietmann(at)pup(dot)ch wrote:

> Hello there
>
> I have still the same problem. Any help would really be appreciated !
> Thanks ... jr
>
> Is it possible (and I think it is) to do the following :
>
> I have a table with diameters and types. I need to build a comma separated
> string.
>
> typ diam
> 01 800
> 01 840
> 01 870
> 01 1120
> 02 760
> 02 780
> 02 800
> 02 900
> 03 1200
> 03 1234
> 03 1352
>
> select diam from zylinder where typ='01'
>
> should produce the string "800,840,870,1120"
>
>
>
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