Re: find and replace the string within a column

From: Jayadevan M <Jayadevan(dot)Maymala(at)ibsplc(dot)com>
To: Nicholas I <nicholas(dot)domnic(dot)i(at)gmail(dot)com>
Cc: pgsql-sql(at)postgresql(dot)org, pgsql-sql-owner(at)postgresql(dot)org
Subject: Re: find and replace the string within a column
Date: 2010-09-24 09:33:37
Message-ID: OFF34DA862.E1543DC5-ON652577A8.00344354-652577A8.003484A7@ibsplc.com
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Hello,
> the below one help's me to find the data within the two brackets.
>
> SELECT name,(REGEXP_MATCHES(name, E'\\(.+?\\)'))[1] from person;
> regexp_matches
> ------------------------------------
> (S/o Sebastin )
> -------------------------------------
>
Trying to work with your code -
update table set name =
substr( name,1,strpos(name, (REGEXP_MATCHES(name, E'\\(.+?\\)')) )-1 ) ||
substr( name,strpos(name, (REGEXP_MATCHES(name, E'\\(.+?\\)')) ) + 1
,char_length(name))

I am trying to find what is there before the pattern and after the pattern
and concatenating them . Please see documentation for proper use of
substr,strpos,cahr_length etc.

Regards,
Jayadevan

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