Re: Double aggregate problem

Hello,

I have the following tables:

CREATE TABLE tblvacature (
id serial PRIMARY KEY,
account int NOT NULL REFERENCES tblaccount (id) ON DELETE CASCADE,

title varchar(128),
bedrijfsprofiel text,
functieomschrijving text,
functieeisen text,
arbeidsvoorwaarden text
overig text,
sollicitatieinfo text,

inserted timestamp DEFAULT now()
);

CREATE TABLE tblvacaturesector ( vacature int NOT NULL REFERENCES
tblvacature (id) ON DELETE CASCADE, sector int NOT NULL REFERENCES
tblsector (id) ON DELETE CASCADE );
select * from tblvacaturesector where vacature = 11;
vacature | sector
----------+--------
11 | 5
11 | 2

CREATE TABLE tblvacatureprovincie ( vacature int NOT NULL REFERENCES
tblvacature (id) ON DELETE CASCADE, provincie int NOT NULL REFERENCES
tblprovincie (id) ON DELETE CASCADE );
select * from tblvacatureprovincie where vacature = 11;
vacature | provincie
----------+-----------
11 | 7
11 | 1
11 | 8

CREATE TABLE tblprovincie (
id serial PRIMARY KEY,
land int NOT NULL REFERENCES tblland (id) ON DELETE RESTRICT,

name varchar(128)
);
select * from tblprovincie;
id | land | name
----+------+-----------------
1 | 1 | Noord-Holland
2 | 1 | Zuid-Holland
3 | 1 | Groningen
4 | 2 | Brabant
5 | 1 | Utrecht
6 | 2 | Antwerpen
7 | 2 | Limburg
8 | 2 | Oost-Vlaanderen

CREATE TABLE tblsector (
id serial PRIMARY KEY,

name varchar(128)
);
select * from tblsector;
id | name
----+---------
4 | Aap
1 | Cool
5 | Eerder
2 | Gaafjes
6 | Later
3 | Netjes
11 | ICT

I hope that's enough information?

> -----Oorspronkelijk bericht-----
> Van: Peter Eisentraut [mailto:peter_e(at)gmx(dot)net]
> Verzonden: woensdag 22 juli 2009 20:05
> Aan: pgsql-sql(at)postgresql(dot)org
> CC: David Weilers
> Onderwerp: Re: [SQL] Double aggregate problem
>
> On Wednesday 22 July 2009 19:16:21 David Weilers wrote:
> > I have the following query:
> >
> > select v.id, array_to_string(array_accum(s.name),', ') as sector ,
> > array_to_string(array_accum(p.name),', ') as provincie from
tblvacature
> > v, tblaccount a , tblvacaturesector vs, tblsector s ,
> > tblvacatureprovincie vp, tblprovincie p where v.id = 11 and
v.account =
> > a.id and vs.vacature = v.id and s.id = vs.sector and vp.vacature =
v.id
> > and p.id = vp.provincie group by v.id, v.inserted order by
v.inserted
> > desc
> >
> > That currently produces the following output:
>
> No one is going to be able to reproduce that without the table
definitions and
> data.
>