From: | Michael Glaesemann <grzm(at)seespotcode(dot)net> |
---|---|
To: | David Fetter <david(at)fetter(dot)org> |
Cc: | Tom Lane <tgl(at)sss(dot)pgh(dot)pa(dot)us>, George Pavlov <gpavlov(at)mynewplace(dot)com>, delux256-postgresql(at)yahoo(dot)com, PostgreSQL GENERAL List <pgsql-general(at)postgresql(dot)org> |
Subject: | Re: Question about a query with two count fields |
Date: | 2007-09-11 19:18:29 |
Message-ID: | ED7CEE79-3174-428F-8708-E4B468C4728B@seespotcode.net |
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Thread: | |
Lists: | pgsql-general |
On Sep 11, 2007, at 13:42 , David Fetter wrote:
> I believe that foo!=bar without white space should simply error out
> because there is no reasonable, unambiguous way to parse it. Here's
> what we get right now:
What's ambigious about it? An operator cannot include a space, so !=
(no space) is *always* interpreted as one operator: not equals (<>).
space (! and = are separate operators), so ! is factorial.
> test=# SELECT (2! =0);
> ?column?
> ----------
> f
> (1 row)
> test=# SELECT (2 ! =0);
> ?column?
> ----------
> f
> (1 row)
> test=# SELECT (2 ! = 0);
> ?column?
> ----------
> f
> (1 row)
>
no space, so != is one operator,
> test=# SELECT (2!=0);
> ?column?
> ----------
> t
> (1 row)
> test=# SELECT (2 != 0);
> ?column?
> ----------
> t
> (1 row)
>
> test=# SELECT (2 !=0);
> ?column?
> ----------
> t
> (1 row)
Michael Glaesemann
grzm seespotcode net
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