Re: 7.3.3 behaving differently on OS X 10.2.6 and FreeBSD 4.8-STABLE

From: "David Olbersen" <DOlbersen(at)stbernard(dot)com>
To: <pgsql-general(at)postgresql(dot)org>
Subject: Re: 7.3.3 behaving differently on OS X 10.2.6 and FreeBSD 4.8-STABLE
Date: 2003-08-08 18:37:51
Message-ID: E7E213858379814A9AE48CA6754F5ECB0D7036@mail01.stbernard.com
Views: Raw Message | Whole Thread | Download mbox | Resend email
Thread:
Lists: pgsql-general

Culley,

> But on my production machine postgresql complained about the order by
> clause-- it wanted the table alias to be on last_name.

I believe this is because you used "u.last_name" earlier in the statement, and the ORDER BY clause doesn't know that's what you mean.

That's a guess that doesn't really explain why it'd work under one OS and not under another. Are the two versions of Postgres configured the same?

--------------------------
David Olbersen
iGuard Engineer
St. Bernard Software

> -----Original Message-----
> From: culley harrelson [mailto:culley(at)fastmail(dot)fm]
> Sent: Friday, August 08, 2003 10:48 AM
> To: pgsql-general(at)postgresql(dot)org
> Subject: [GENERAL] 7.3.3 behaving differently on OS X 10.2.6
> and FreeBSD
> 4.8-STABLE
>
>
> I don't know if this is a postgresql bug or a problem with my
> architecture but I thought I would post here about a strange
> bug I just
> came across in my application.
>
> I use OS X 10.2.6 as my development machine and FreeBSD 4.8 for my
> production machines. All systems are running postgresql
> 7.3.3. I just
> published some code to production and when testing the production
> results it blew up with a sql parsing error. The following
> sql worked
> fine on my OS X development machine:
>
> select u.user_id, u.first_name, u.last_name, u.email_address, w.w9,
> pm.description as payment_method, count(s.user_id) as documents,
> sum(s.payment_amount) as amt_sum from ht_user u inner join
> writer w on
> u.user_id = w.user_id inner join payment_method pm on
> w.payment_method_id = pm.payment_method_id left join submission s on
> u.user_id = s.user_id group by u.user_id, u.first_name, u.last_name,
> u.email_address, w.w9, pm.description order by lower(last_name) asc
>
> But on my production machine postgresql complained about the order by
> clause-- it wanted the table alias to be on last_name.
>
> culley
>
>
>
> ---------------------------(end of
> broadcast)---------------------------
> TIP 7: don't forget to increase your free space map settings
>

Responses

Browse pgsql-general by date

  From Date Subject
Next Message Anthony Best 2003-08-08 19:01:01 Anomaly with SUM().
Previous Message Dmitry Tkach 2003-08-08 18:31:57 Trying to create a GiST index in 7.3