On Apr 10, 2008, at 7:39 AM, Gaetano Mendola wrote:
> Hi all,
> specifing as shared_buffers = 26800 in 8.2.x will this value
> accepted like
> in the 8.1.x series and then 26800*8192 bytes = 209 MB or 26800 bytes
> (not being specified the memory unit)?
With no specified unit then it defaults to 8K.
Erik Jones
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