Re: How to get the position of each record in a SELECT statement

El 07/10/2016, a las 19:20, JORGE MALDONADO <jorgemal1960(at)gmail(dot)com> escribió:

> Let´s say that I have the following simple SELECT statement:
>
> SELECT first, id FROM customers ORDER BY first
>
> This would result in something like this:
> Charles C1001
> John A3021
> Kevin F2016
> Paul N4312
> Steve J0087
>
> Is it possible to include a "field" in the SELECT such that it represents the position of each record?
> For example, I need to get a result like this:
>
> 1 Charles C1001
> 2 John A3021
> 3 Kevin F2016
> 4 Paul N4312
> 5 Steve J0087
>
> Respectfully,
> Jorge Maldonado

Hi:

If you need the order in the result (not physically) can try this code:

SELECT
(SELECT COUNT(*)
FROM customers o
WHERE (o.first = c.first) and (o.id = c.id)) AS position,
c.first,
c.id
FROM customers c
order by c.first

Hope this help,
Best regards.