From: | Eric Ridge <ebr(at)tcdi(dot)com> |
---|---|
To: | Jerry LeVan <jerry(dot)levan(at)eku(dot)edu> |
Cc: | Postgres General <pgsql-general(at)postgresql(dot)org> |
Subject: | Re: Folding subtotals into query? |
Date: | 2004-04-18 20:20:27 |
Message-ID: | D48FF71E-9175-11D8-91AB-000A95BB5944@tcdi.com |
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Thread: | |
Lists: | pgsql-general |
On Apr 18, 2004, at 4:07 PM, Jerry LeVan wrote:
> That does the job, for 3200 checks it does chug for a while, too bad
> it can't remember the intermediate results :)
hmm... Can do this via a left join too. Much faster:
SELECT checks.*, x.sum
FROM checks
LEFT JOIN (SELECT category, sum(amount) AS sum FROM checks GROUP BY
category) AS x ON x.category = checks.category
ORDER BY category, sum
eric
>
> --Jerry
>
> On Apr 18, 2004, at 3:10 PM, Eric Ridge wrote:
>
>> On Apr 18, 2004, at 2:41 PM, Jerry LeVan wrote:
>>
>>> Is is possible, via some clever sql coding ( perhaps with PL/pgsql)
>>> to get subtotals to appear in a selection, ie
>>>
>>> If I have a query: select * from checks order by category
>>> I would like the have the subtotals appear (possibly in
>>> an unused column for each "category" when the category
>>> "breaks".
>>>
>>> Basically I would like to meld the query:
>>> select category, sum(amount) from checks group by category order by
>>> category
>>
>> I think you want to do something like this:
>>
>> SELECT *, (SELECT sum(amount) FROM checks AS x WHERE x.category =
>> checks.category GROUP BY x.category) AS total
>> FROM checks
>> ORDER BY category;
>>
>> This will give you a column named "total" for every row in checks.
>> The value will be the sum(amount) for the corresponding category.
>> You'll likely want an index on checks.category to get any level of
>> tolerable performance out of the query.
>>
>> eric
>>
>
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