From: | "Oliveiros d'Azevedo Cristina" <oliveiros(dot)cristina(at)marktest(dot)pt> |
---|---|
To: | "Michele Petrazzo - Unipex" <michele(dot)petrazzo(at)unipex(dot)it> |
Cc: | <pgsql-sql(at)postgresql(dot)org> |
Subject: | Re: group by hour + distinct |
Date: | 2010-11-26 13:15:14 |
Message-ID: | D352FB1B6AD34FC1A0E5052DB2A786A5@marktestcr.marktest.pt |
Views: | Raw Message | Whole Thread | Download mbox | Resend email |
Thread: | |
Lists: | pgsql-sql |
>
> Ciao
>
* Olá!
>> for each hour it will count the number of distinct user_id's there
>> are . If I understood correctly what you need...
>>
>> Can you please test it and see if it is OK for your needs? With me,
>> it worked on the sample data you provided
>>
>
> Yes! Simply perfect!
>
* Great to hear it worked !
>>
>
> Thanks,
> Michele
* Don't mention it ;-)
>
> P.s. Have you some references about the "subquery" keyword? I found only
> the word subquery as "use" (for example: select a from b where id in
> (select id from table)), but not as sql command.
>
>
* I don't know subquery as an SQL keyword too. In the query I gave you the
"subquery" thing was just an alias. Such kind of things are mandatory. If I
try to omit it, I get this error
ERROR: subquery in FROM must have an alias
HINT: For example, FROM (SELECT ...) [AS] foo.
********** Erro **********
ERROR: subquery in FROM must have an alias
Estado de SQL:42601
Sugestão:For example, FROM (SELECT ...) [AS] foo.
So, even though the "subquery" alias was not used anywhere else, I believe
it had to be there, otherwise the SQL parser would complain
Best,
Oliver
From | Date | Subject | |
---|---|---|---|
Next Message | Lew | 2010-11-26 16:07:05 | Re: group by hour + distinct |
Previous Message | Michele Petrazzo - Unipex | 2010-11-26 12:42:55 | Re: group by hour + distinct |