From: | Zhenghua Lyu <zlv(at)pivotal(dot)io> |
---|---|
To: | PostgreSQL Hackers <pgsql-hackers(at)lists(dot)postgresql(dot)org> |
Subject: | On disable_cost |
Date: | 2019-11-01 06:42:25 |
Message-ID: | CAO0i4_SSPV9TVxbbTRVLOnCyewopcc147fBZy=f2ABk15eHS+g@mail.gmail.com |
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Lists: | pgsql-hackers |
Hi,
Postgres has a global variable `disable_cost`. It is set the value
1.0e10.
This value will be added to the cost of path if related GUC is set off.
For example,
if enable_nestloop is set off, when planner trys to add nestloop join
path, it continues
to add such path but with a huge cost `disable_cost`.
But 1.0e10 may not be large enough. I encounter this issue in
Greenplum(based on postgres).
Heikki tolds me that someone also encountered the same issue on Postgres.
So I send it here to
have a discussion.
My issue: I did some spikes and tests on TPCDS 1TB Bytes data. For
query 104, it generates
nestloop join even with enable_nestloop set off. And the final plan's
total cost is very huge (about 1e24). But If I enlarge the disable_cost to
1e30, then, planner will generate hash join.
So I guess that disable_cost is not large enough for huge amount of
data.
It is tricky to set disable_cost a huge number. Can we come up with
better solution?
The following thoughts are from Heikki:
> Aside from not having a large enough disable cost, there's also the
> fact that the high cost might affect the rest of the plan, if we have to
> use a plan type that's disabled. For example, if a table doesn't have any
> indexes, but enable_seqscan is off, we might put the unavoidable Seq Scan
> on different side of a join than we we would with enable_seqscan=on,
> because of the high cost estimate.
> I think a more robust way to disable forbidden plan types would be to
> handle the disabling in add_path(). Instead of having a high disable cost
> on the Path itself, the comparison add_path() would always consider
> disabled paths as more expensive than others, regardless of the cost.
Any thoughts or ideas on the problem? Thanks!
Best Regards,
Zhenghua Lyu
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