| From: | Akshay Joshi <akshay(dot)joshi(at)enterprisedb(dot)com> |
|---|---|
| To: | Edson Richter <edsonrichter(at)hotmail(dot)com> |
| Cc: | "pgadmin-support lists(dot)postgresql(dot)org" <pgadmin-support(at)lists(dot)postgresql(dot)org> |
| Subject: | Re: pgAdmin 4.20 and 4.21 cannot create foreign key |
| Date: | 2020-05-04 08:18:22 |
| Message-ID: | CANxoLDeOzp7Yq0O=+4zKHYOpUr2PvZqc+rnKaZghWwKmKuVbKQ@mail.gmail.com |
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| Thread: | |
| Lists: | pgadmin-support |
Hi Edson
I have tried on PostgreSQL 9.6 and 10, not able to reproduce the issue. Can
you please provide the exact steps and the example table?
On Sun, May 3, 2020 at 12:20 AM Edson Richter <edsonrichter(at)hotmail(dot)com>
wrote:
> Using PostgreSQL 9.6 on Linux Centos 7 x64 - yum standard installer.
> pgAdmin 4.20 and 4.21 on Windows Server 2019 x64 - .exe standard installer.
>
> I'm trying to create a foreign key using 4.20 and didn't wored: keep
> always asking to create a covering index.
> Tryied in 4.20 and also in 4.21 with same results
>
> Follow the screenshot of the error:
>
>
>
--
*Thanks & Regards*
*Akshay Joshi*
*Sr. Software Architect*
*EnterpriseDB Software India Private Limited*
*Mobile: +91 976-788-8246*
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