From: | David Rowley <david(dot)rowley(at)2ndquadrant(dot)com> |
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To: | Michael Paquier <michael(dot)paquier(at)gmail(dot)com> |
Cc: | Amit Langote <Langote_Amit_f8(at)lab(dot)ntt(dot)co(dot)jp>, Peter Eisentraut <peter(dot)eisentraut(at)2ndquadrant(dot)com>, Robert Haas <robertmhaas(at)gmail(dot)com>, Pg Hackers <pgsql-hackers(at)postgresql(dot)org> |
Subject: | Re: [Sender Address Forgery]Re: pg_(total_)relation_size and partitioned tables |
Date: | 2018-01-21 06:16:38 |
Message-ID: | CAKJS1f-mffi=9Kjynns4L4Oc0YN7dJfB=SKyYZH-8bDZ5=q9qg@mail.gmail.com |
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Lists: | pgsql-hackers |
On 20 January 2018 at 23:14, Michael Paquier <michael(dot)paquier(at)gmail(dot)com> wrote:
> If pg_partition_tree_tables() uses the top of the partition as input,
> all the tree should show up. If you use a leaf, anything under the leaf
> should show up. If a leaf is defined and it has no underlying leaves,
> then only this outmost leaf should be listed.
hmm, that's thoroughly confusing. Just in case anyone else is stuck on
that, I just need to mention that a leaf is the does not have
branches, in nature or computer science.
--
David Rowley http://www.2ndQuadrant.com/
PostgreSQL Development, 24x7 Support, Training & Services
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