From: | "David G(dot) Johnston" <david(dot)g(dot)johnston(at)gmail(dot)com> |
---|---|
To: | Pál Teleki <ellenallhatatlan(at)gmail(dot)com> |
Cc: | pgsql-novice novice <pgsql-novice(at)postgresql(dot)org> |
Subject: | Re: 2nd attempt: Window function SQL - can't quite figure it. |
Date: | 2016-07-18 19:31:52 |
Message-ID: | CAKFQuwbw60ONuYjsF7D_5XS3cyfRJQz6Mm+QH+iVpiX1EMpYTQ@mail.gmail.com |
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Lists: | pgsql-novice |
On Mon, Jul 18, 2016 at 3:24 PM, Pál Teleki <ellenallhatatlan(at)gmail(dot)com>
wrote:
> Thanks for that - I managed
>
> > SELECT *, total_mgr_dept / total_dept_only AS manager_share_of_department
> > <rest of query snipped...>
>
> I managed to do using two CTEs as shown below.
>
> I was wondering, how would it be possible to do what I want
> using traditional SQL? That is, no CTE's and no Windowing
> functions?
>
> ====== My effort using two CTE's ====
>
> WITH tab1 AS (
> SELECT department, salesmanager, SUM(amount) as sm1 FROM sales
> GROUP BY department, salesmanager
> ),
> tab2 AS (
> SELECT department, SUM(amount) as sm2 FROM sales
> GROUP BY department
> )
> SELECT tab1.*, tab2.sm2, ROUND((tab1.sm1/tab2.sm2) * 100, 2) AS "%age
> of Dept. income"
> FROM tab1
> INNER JOIN tab2 ON
> tab1.department = tab2.department;
>
>
Correlated subqueries.
Not tested, should at least give an idea even if it has an error
SELECT s1.department, s1.salesmanager,
(SELECT sum(s2.amount) FROM sales s2 WHERE
s2.department = s1.department) AS total_for_the_entire_department
FROM sales s1
GROUP BY s1.department, s1.salesmanager
Or just stick your CTE into a subquery FROM
FROM tab1
becomes
FROM (SELECT [...] GROUP BY department, salesmanager) tab1
Given the data, and the absence of any other filters, there shouldn't be
any true difference between the two forms though I do not know about about
the planner to know whether there is a difference in reality.
David J.
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