| From: | "David G(dot) Johnston" <david(dot)g(dot)johnston(at)gmail(dot)com> |
|---|---|
| To: | Steve Midgley <science(at)misuse(dot)org> |
| Cc: | Shaozhong SHI <shishaozhong(at)gmail(dot)com>, Christophe Pettus <xof(at)thebuild(dot)com>, pgsql-sql <pgsql-sql(at)lists(dot)postgresql(dot)org> |
| Subject: | Re: How best to work around the issue - regex string cannot contain brackets |
| Date: | 2022-02-04 17:24:24 |
| Message-ID: | CAKFQuwbhQBNQkapttj9KfFTyQkQfvF+wO2EjrkdkY8q_e8MUew@mail.gmail.com |
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| Lists: | pgsql-sql |
On Fri, Feb 4, 2022 at 10:14 AM Steve Midgley <science(at)misuse(dot)org> wrote:
>
>
> On Fri, Feb 4, 2022 at 6:01 AM Shaozhong SHI <shishaozhong(at)gmail(dot)com>
> wrote:
>
>> It appears that the following regex work differently.
>>
>> Why \d and [\d] are different?
>>
>> [A-PR-UWYZ]\d{1,2} and [A-PR-UWYZ][\d]{1,2}
>>
>
Show your work!
> But when you put characters into brackets, you are telling regex to search
> for each character represented in the bracket. So [\d] is looking for any
> single character that is either a \ or a d character. Outside of brackets,
> regex evaluates \d as any digit.
>
This is simply wrong. Test it.
David J.
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