Re: Hi

From: "David G(dot) Johnston" <david(dot)g(dot)johnston(at)gmail(dot)com>
To: Daulat Ram <Daulat(dot)Ram(at)cyient(dot)com>
Cc: "pgsql-performance(at)postgresql(dot)org" <pgsql-performance(at)postgresql(dot)org>
Subject: Re: Hi
Date: 2017-08-25 14:42:20
Message-ID: CAKFQuwaJ=xhBL4oWAayTj9-rUC4owNeopxi4c4HyW1WG-SnK8g@mail.gmail.com
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On Thu, Aug 24, 2017 at 11:49 PM, Daulat Ram <Daulat(dot)Ram(at)cyient(dot)com> wrote:

> Hello,
>
>
>
> Would I request to help me on this query.
>
>
>
> SELECT 'Inspection Completed' as "ALL Status" ,COUNT(*) as "Number of
> Count" FROM ud_document WHERE status = 'Inspection Completed' union SELECT
> 'Pending', COUNT(*) FROM ud_document WHERE status = 'Pending' union SELECT
> 'Approved', COUNT(*) FROM ud_document WHERE status = 'Approved' union
> SELECT 'Rejected', COUNT(*) FROM ud_document WHERE status = 'Rejected'
> union SELECT 'Payment Due',count(*) from ud_document where payment_status =
> 'Payment Due' union SELECT 'Payment Done' ,count(*) from ud_document where
> payment_status = 'Payment Done'
>
>
>
> And now I want to exclude the uniqueid= '201708141701018' from the above
> query. how it can be ???
>
>
>
​Your use of UNION here seems necessary. Just write a normal GROUP BY
aggregation query. You might need to get a bit creative since you are
collapsing status and payment_status into a single column. "CASE ... WHEN
... THEN ... ELSE ... END" is quite helpful for doing stuff like that. For
now I'll just leave them as two columns.

​SELECT status, payment_status, count(*)
FROM ud_document
WHERE uniqueid <> '201708141701018'
GROUP BY 1, 2;

David J.

In response to

  • Re: Hi at 2017-08-25 06:49:07 from Daulat Ram

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