Re: Using functions in regexp replace captures

On Wednesday, August 4, 2021, David G. Johnston <david(dot)g(dot)johnston(at)gmail(dot)com>
wrote:

>
> But no, you cannot directly write: f(x, y, g(a)) where a is the
> replacement string because you don’t know what a is when the inner function
> g is evaluated first. You need: f(x, y, g(h(x, y))) where h is the
> matching function, g is the transform, f is the replacement of the third
> argument into the x source text, and y is the pattern. I presume the y is
> going to be the same value here but that isn’t required.
>
>
“a” is actually probably going to be an array of text here, its evaluation
producing the replacement string that f requires. a is not the replacement
string itself.

David J.