From: | Pavel Stehule <pavel(dot)stehule(at)gmail(dot)com> |
---|---|
To: | Sandeep Gupta <gupta(dot)sandeep(at)gmail(dot)com> |
Cc: | pgsql-general(at)postgresql(dot)org |
Subject: | Re: group by query plan on already clustered index |
Date: | 2013-07-25 15:14:37 |
Message-ID: | CAFj8pRA_EK+DUT_8x7t-V8sE0gFzCOwqiyOy5vd=N=utaFX2nw@mail.gmail.com |
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Lists: | pgsql-general |
Hello
2013/7/25 Sandeep Gupta <gupta(dot)sandeep(at)gmail(dot)com>:
> On a table T with two fields, f1 and f2, the sql command
>
> select count(f2), f1
> from T
> group by f1
>
> result is seq scan followed by a sort on f1 (see the query plan below):
>
> GroupAggregate (cost=21566127.88..22326004.09 rows=987621 width=8)
> -> Sort (cost=21566127.88..21816127.88 rows=100000000 width=8)
> Sort Key: pid
> -> Seq Scan on tc (cost=0.00..1442478.00 rows=100000000 width=8)
>
>
> However, the table is already has clustered index on f1. My question is why
> doesn't
> postgres simply scan the table and compute the group? Why it needs to sort
> on f1 again?
> How can I force postgres to use the clustered index for group by?
>
PostgreSQL doesn't support index organized tables. Statement CLUSTER
doesn't ensure order of heap for ever. After any INSERT, UPDATE you
can lost a order.
So every time, you have to check order.
PostgreSQL 9.2 support a index only scan - but it is not used in your plan.
Regards
Pavel Stehule
>
> Thanks.
> Sandeep
>
>
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