Re: ERROR: relation "sql_features" does not exist

From: Pavel Stehule <pavel(dot)stehule(at)gmail(dot)com>
To: Tom Lane <tgl(at)sss(dot)pgh(dot)pa(dot)us>
Cc: PostgreSQL Hackers <pgsql-hackers(at)lists(dot)postgresql(dot)org>
Subject: Re: ERROR: relation "sql_features" does not exist
Date: 2021-04-26 17:14:50
Message-ID: CAFj8pRANQAdPNqfZ0c7pESngw3SwuW38rQ-NT+YqmQP4Mv0_gA@mail.gmail.com
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po 26. 4. 2021 v 19:10 odesílatel Tom Lane <tgl(at)sss(dot)pgh(dot)pa(dot)us> napsal:

> Pavel Stehule <pavel(dot)stehule(at)gmail(dot)com> writes:
> > I tried to write a query that does lateral join between
> > information_schema.tables and pgstattuple function.
>
> > select * from information_schema.tables, lateral(select * from
> > pgstattuple(table_name::name)) s where table_type = 'BASE TABLE';
>
> > The query finished by strange error
>
> > postgres=# select * from information_schema.tables, lateral(select * from
> > pgstattuple(table_name::name)) s where table_type = 'BASE TABLE';
> > ERROR: relation "sql_features" does not exist
>
> > When I set search_path to information_schema, then the query is running.
> > But there is not any reason why it should be necessary.
>
> Nope, this is classic user error, nothing else. "table_name::name"
> is entirely inadequate as a way to reference a table that isn't
> visible in your search path. You have to incorporate the schema
> name as well.
>
> Ideally you'd just pass the table OID to the OID-accepting version of
> pgstattuple(), but of course the information_schema schema views
> don't expose OIDs. So basically you need something like
>
>
> pgstattuple((quote_ident(table_schema)||'.'||quote_ident(table_name))::regclass)
>
> although perhaps format() could help a little here.
>

I understand now. Thank you for explanation

select * from information_schema.tables, lateral(select * from
pgstattuple(format('%I.%I', table_schema, table_name))) s where table_type
= 'BASE TABLE';

This is working

Regards

Pavel

>
> regards, tom lane
>

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