Re: row filtering for logical replication

From: Dilip Kumar <dilipbalaut(at)gmail(dot)com>
To: Tomas Vondra <tomas(dot)vondra(at)enterprisedb(dot)com>
Cc: Amit Kapila <amit(dot)kapila16(at)gmail(dot)com>, Euler Taveira <euler(at)eulerto(dot)com>, Alvaro Herrera <alvherre(at)alvh(dot)no-ip(dot)org>, Peter Smith <smithpb2250(at)gmail(dot)com>, Rahila Syed <rahilasyed90(at)gmail(dot)com>, Peter Eisentraut <peter(dot)eisentraut(at)enterprisedb(dot)com>, Önder Kalacı <onderkalaci(at)gmail(dot)com>, japin <japinli(at)hotmail(dot)com>, Michael Paquier <michael(at)paquier(dot)xyz>, David Steele <david(at)pgmasters(dot)net>, Craig Ringer <craig(at)2ndquadrant(dot)com>, Tomas Vondra <tomas(dot)vondra(at)2ndquadrant(dot)com>, Amit Langote <amitlangote09(at)gmail(dot)com>, PostgreSQL Hackers <pgsql-hackers(at)lists(dot)postgresql(dot)org>
Subject: Re: row filtering for logical replication
Date: 2021-07-14 14:48:34
Message-ID: CAFiTN-vcY1DzqpnCKWEeees22zcfeoj6_oiO9eAJjgPBoRR-1g@mail.gmail.com
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On Wed, Jul 14, 2021 at 8:04 PM Tomas Vondra
<tomas(dot)vondra(at)enterprisedb(dot)com> wrote:
>

> Perhaps the best way forward is to stick to the approach that INSERT
> uses new, DELETE uses old and UPDATE works as DELETE+INSERT (probably),
> and leave anything fancier (like being able to reference both versions
> of the row) for a future patch.

If UPDATE works as DELETE+ INSERT, does that mean both the OLD row and
the NEW row should satisfy the filter, then only it will be sent?
That means if we insert a row that is not satisfying the condition
(which is not sent to the subscriber) and later if we update that row
and change the values such that the modified value matches the filter
then we will not send it because only the NEW row is satisfying the
condition but OLD row doesn't. I am just trying to understand your
idea. Or you are saying that in this case, we will not send anything
for the OLD row as it was not satisfying the condition but the
modified row will be sent as an INSERT operation because this is
satisfying the condition?

--
Regards,
Dilip Kumar
EnterpriseDB: http://www.enterprisedb.com

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