Re: Help : Sum 2 tables based on key from other table

If the tables aren't huge, you're not concerned about optimization, and you
just want to get your numbers, I think something like this would do the
trick. I haven't actually tried it 'cause I didn't have easy access to
your tables:

SELECT
a.product_id,
a.product_name,
b.initial_stock_sum,
c.in_out_sum,
c.in_sum,
c.out_sum
FROM
a
LEFT JOIN
(SELECT
product_id,
SUM(initial_stock) AS initial_stock_sum
FROM b
GROUP BY product_id
) b USING (product_id)
LEFT JOIN
(SELECT
product_id,
sum(CASE WHEN date < 'BEGINNING DATE' THEN in-out ELSE 0 END) AS
in_out_sum,
sum(CASE WHEN date BETWEEN 'BEGINNING DATE' AND 'ENDING DATE' THEN in
ELSE 0 END) AS in_sum,
sum(CASE WHEN date BETWEEN 'BEGINNING DATE' AND 'ENDING DATE' THEN out
ELSE 0 END) AS out_sum
FROM c
GROUP BY product_id
) c USING (product_id)
WHERE a.supplier_id='XXX';

Cheers,
Ken

On Mon, Nov 18, 2013 at 12:47 AM, Raymond O'Donnell <rod(at)iol(dot)ie> wrote:

> On 18/11/2013 02:16, Hengky Liwandouw wrote:
> > Dear Friends,
> >
> > Please help for the select command, as i had tried many times and
> > always can not display the result as what i want.
> >
> > I am looking for the solution on google but still can not found the
> > right answer to solve the problem.
> >
> > I have 3 tables :
> >
> > Table A ProductID ProductName SupplierID
> >
> > Table B ProductID InitialStock
> >
> > Table C ProductID Date In Out
> >
> > 1. I want to select all productID from Table A where
> > supplierID='XXX'.
> >
> > 2. Based on list from Step.1 : sum the initialstock from Table B
> >
> > 3. Based on list from Step 1 : Sum (in-out) from Table C where date
> > <'BEGINNING DATE'
> >
> > 4. Based on list from Step 1 : Sum (in) and sum(out) from Table C
> > where date between 'BEGINNING DATE' and 'ENDING DATE'
> >
> > So the result will look like this :
> >
> > ProductID ProductName SumofIntialStock sum(in-Out)<beginningdate
> > SumofIN SumofOut xxxx xxxxxxxxxxxxx 99
> > 99 99 99 xxxx
> > xxxxxxxxxxxxx 99 99
> > 99 99 xxxx xxxxxxxxxxxxx 99
> > 99 99 99 xxxx
> > xxxxxxxxxxxxx 99 99
> > 99 99
>
> You could try using common table expressions, which let you build up to
> your final result in steps. Some reading:
>
> http://www.postgresql.org/docs/9.3/static/queries-with.html
>
>
> http://www.chesnok.com/daily/2013/11/12/how-i-write-queries-using-psql-ctes/
>
>
> Ray.
>
>
> --
> Raymond O'Donnell :: Galway :: Ireland
> rod(at)iol(dot)ie
>
>
> --
> Sent via pgsql-general mailing list (pgsql-general(at)postgresql(dot)org)
> To make changes to your subscription:
> http://www.postgresql.org/mailpref/pgsql-general
>

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