Re: Subquery to select max(date) value

From: Ken Tanzer <ken(dot)tanzer(at)gmail(dot)com>
To: Rich Shepard <rshepard(at)appl-ecosys(dot)com>
Cc: "pgsql-generallists(dot)postgresql(dot)org" <pgsql-general(at)lists(dot)postgresql(dot)org>
Subject: Re: Subquery to select max(date) value
Date: 2019-03-28 23:21:59
Message-ID: CAD3a31US2nNsY5jhasTMDHixK3WQJnnCi_2hyQY5vsgUGsOaTw@mail.gmail.com
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On Thu, Mar 28, 2019 at 4:14 PM Rich Shepard <rshepard(at)appl-ecosys(dot)com>
wrote:

> On Thu, 28 Mar 2019, Ken Tanzer wrote:
>
> > You need the ORDER BY in the outer join.
>
> Ken,
>
> I thought so. But, ...
>
> > (And I don't think the one inside the lateral join is doing you any
> good).
> > Try:
> > ...
> > a.next_contact is not null
> > limit 1) sq
> > order by sq.next_contact DESC;
>
> This re-orders the returned set, but still not in chronological order.
>

Really? Is your next_contact field a date field and not a text field?
What order does it come out in?

(And I assume you saw David J's correction to the misinformation I offered.)

Cheers,
Ken

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