From: | Marcin Krawczyk <jankes(dot)mk(at)gmail(dot)com> |
---|---|
To: | Alvaro Herrera <alvherre(at)2ndquadrant(dot)com> |
Cc: | "pgsql-sql(at)postgresql(dot)org" <pgsql-sql(at)postgresql(dot)org> |
Subject: | Re: regexp_replace behavior |
Date: | 2012-11-20 15:02:29 |
Message-ID: | CABnqL329i_eb7fUa3iGpG=_SHpLrkd_wG4hfF1SQosyAqQgzUg@mail.gmail.com |
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Lists: | pgsql-sql |
Yes that's exactly what I needed. Thanks a lot.
pozdrowienia
mk
2012/11/20 Alvaro Herrera <alvherre(at)2ndquadrant(dot)com>
> Marcin Krawczyk escribió:
> > Hi list,
> >
> > I'm trying to use regexp_replace to get rid of all occurrences of
> > certain sub strings from my string.
> > What I'm doing is:
> >
> > SELECT regexp_replace('F0301 305-149-101-0 F0302 {x1} 12W47 0635H
> > {tt}{POL23423423}', E'\{.+\}', '', 'g')
> >
> > so get rid of whatever is between { } along with these,
> >
> > but it results in:
> > 'F0301 305-149-101-0 F0302 '
> >
> > how do I get it to be:
> > 'F0301 305-149-101-0 F0302 12W47 0635H'
> >
> > ??
> >
> > as I understood the docs, the g flag "specifies replacement of each
> > matching substring rather than only the first one"
>
> The first \{.+\} match starts at the first { and ends at the last },
> eating the {s and }s in the middle. So there's only one match and that's
> what's removed.
>
> > what am I missing ?
>
> You need a non-greedy quantifier. Try
>
> SELECT regexp_replace('F0301 305-149-101-0 F0302 {x1} 12W47 0635H
> {tt}{POL23423423}', E'\{.+?\}', '', 'g')
>
> --
> Álvaro Herrera http://www.2ndQuadrant.com/
> PostgreSQL Development, 24x7 Support, Training & Services
>
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