From: | Amit Kapila <amit(dot)kapila16(at)gmail(dot)com> |
---|---|
To: | "Jameson, Hunter 'James'" <hunjmes(at)amazon(dot)com> |
Cc: | "pgsql-hackers(at)postgresql(dot)org" <pgsql-hackers(at)postgresql(dot)org> |
Subject: | Re: Fix for parallel BTree initialization bug |
Date: | 2020-09-10 11:58:05 |
Message-ID: | CAA4eK1+ss8TsnC7QwDPax_Fp+Wc24wrgCmCJ1T8-oxGw9car1w@mail.gmail.com |
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On Tue, Sep 8, 2020 at 11:55 PM Jameson, Hunter 'James'
<hunjmes(at)amazon(dot)com> wrote:
>
> Hi, I ran across a small (but annoying) bug in initializing parallel BTree scans, which causes the parallel-scan state machine to get confused. The fix is one line; the description is a bit longer—
>
>
>
> Before, function _bt_first() would exit immediately if the specified scan keys could never be satisfied--without notifying other parallel workers, if any, that the scan key was done.
>
The first question that comes to mind is how is it possible that for
one of the workers specified scan keys is not satisfied while for
others it is satisfied? I think it is possible when other workers are
still working on the previous scan key and this worker has moved to
the next scan key. If not, then what is the other case?
> This moved that particular worker to a scan key beyond what was in the shared parallel-query state, so that it would later try to read in "InvalidBlockNumber", without recognizing it as a special sentinel value.
>
Now, if it happens as I mentioned then the other workers should not
try to advance their scan because their local scan key will be lesser
than shared key. Basically, they should return from the below
condition:
_bt_parallel_seize()
{
..
if (so->arrayKeyCount < btscan->btps_arrayKeyCount)
{
/* Parallel scan has already advanced to a new set of scankeys. */
status = false;
}
..
}
After this, those workers will also update their scan key and move
forward from there. So, I am not seeing how this could create a
problem.
--
With Regards,
Amit Kapila.
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