Re: How to create function returning numeric from string containing percent character

I suspect it will depend on your localisation whether you need to account
for different decimal separators, but just in case:

SELECT replace(substring('-1,2%' from '^-?\d*[.,]?\d*'), ',', '.')::numeric;

On Wed, 22 Jul 2020 at 18:50, Andrus <kobruleht2(at)hot(dot)ee> wrote:

> val function should return numeric value from string up to first non-digit
> character, considering first decimal point also:
>
> val('1,2TEST') should return 1.2
> val('1,2,3') should return 1.2
> val('-1,2,3') should return -1.2
>
> I tried
>
> CREATE OR REPLACE FUNCTION public.VAL(value text)
> RETURNS numeric AS
> $BODY$
> SELECT coalesce(nullif('0'||substring(Translate($1,',','.'),
> '^-?[0-9]+\.?[0-9]*$'),''),'0')::numeric;
> $BODY$ language sql immutable;
>
> but if string contains % character,
>
> select val('1,2%')
>
> returns 0.
>
> How to force it to return 1.2 ?
>
> It should work starting from Postgres 9.0
>
> Posted also in
>
>
> https://stackoverflow.com/questions/63032072/how-to-create-function-returning-value-up-to-first-non-digit-decimal-charcater#63032126
>
> Andrus.
>
>
>
>

--

[image: Ausvet Logo] <https://www.ausvet.com.au/>

Dr Ben Madin

BVMS MVPHMgmt PhD MANZCVS GAICD
Managing Director
Mobile:
+61 448 887 220 <+61448887220>
E-mail:
ben(at)ausvet(dot)com(dot)au
Website:
www.ausvet.com.au
Skype: benmadin
Address:
5 Shuffrey Street
Fremantle, WA 6160
Australia